Bash regex for number how to#
There's a quick YouTube tutorial on how to use the builder. to ensure you're creating what you desire as its unclear to me from what you've posted. I highly recommend you visit Regxr and use the on-line Regex expression builder there to create and test your expression. From your description, I don't think that's what you desire. The final * before the last closing parens would again be a 'greedy match` that due to it's placement I believe would cause the entire pattern search to repeat. Note that bash stores the first matched sub-pattern indicated by enclosing parenthesis in the regular expression in the special variable BASHREMATCH 1 extract. This stream-oriented editor was created exclusively for executing scripts. Regular expressions are used by several different Unix commands, including ed, sed, awk, grep, and to a more limited extent, vi. I'm not totally certain of that, but I believe that would be the case. This short script demonstrate how to use the regular expressions for numbers to extract numbers and numeric data from unstructured text, a common problem in this age of the Internet. A regular expression is a string that can be used to describe several sequences of characters. Is that something you also don't want to allow? The - following it isn't applicable in terms of a range of characters and thus would likely only apply when it follows an apostrophe meaning Regex would look for '. It appears that you've also escaped an apostrophe with the \'. The same would apply to the * you have following the second set of alpha characters. So, I don't think you want the * there if you want to prevent single characters using Regex. Which would be where you have the \\s\\ that represents a whitespace. Will match as many characters as possible before satisfying the next
* Matches 0 or more of the preceeding token.
In the above, the first * is a 'greedy match', meaning it
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